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What is the oxidation state for the atoms in the reaction: 2 Al + 8 H2O → 2 H+1 + 3 H2 + 2 Al(OH)4-1
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\(Al = 3^+\), water is neutral, If you want to find out the oxidation state for Aluminum tetroxide, you can set up a relatively easy algebraic expression: x + 4(-1) = -1 the "x" represents the oxidation state of aluminum for which you are solving for, the "4" represents the four hydroxides attached to aluminum. the "(-1)" represents the negative charge on the hydroxide. You multiply it by 4 because there are FOUR hydroxide atoms, total of -4. and the "= -1" is the charge of the molecule. Now, solving for x, you get: 3+ Hence, the oxidation state of aluminum is 3+
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