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integration of 5tanx/(tanx-2) how do i approach this?
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\(5 \int\limits \frac{ \tan(x) }{ \tan(x)-2 }dx\) Is this correct?
Yep.
You COULD convert: \(tan(x)= \frac{ \sin(x) }{ \cos(x) }\) and try and simplify.
Doesnt help i guess. Unless you can come up with something. sinx/(sinx-2cosx) dx is what i get.
it is simple put tan(x)-2=u and simplify
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Ok so sec^2x dx=du what i get is (t+2)/(sec^2x*t) dt.. what next @irshadno1 ?
1 + tan^2x = sec^2
Yeah i got it. What we have to do is, put tanx=t, solve put sec^2=1+t^2... use partial fractions and simplify. I was forgetting to use partial fractions. You were the closest. Thank you.
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