Question

9x + 3y – 6z = 18

Answer 1

Are you looking for X, Y and Z???

Answer 2

yes @BABYShawol184

Answer 3

Well there are many solutions. It's up to you. For example i will decide to make x =0

Therefore...
\[9(0) + 3y -6z=18\]
\[3y-6z=18\]
Now we can choose to solve for Y or Z so I will solve for Y

So...
\[3y = 18+6z\]
Now to isolate for Y we divide each side by 3
\[y = (18 +6z)\div3\]
Now that we have Y we can insert it into the equation
\[3y-6z=18\]
Therefore...
\[((18+6z)\div3)-6z = 8\]
So when subtracting a fraction by a number we find a common denominator between the two terms usually by multiplying so in this case we will multiply 6z (which is actually over 1) by 3 then we can add it to 18 + 6z
So...
\[(18+6z-18z)\div3 = 18\]
Now because we have one term we can solve for Z starting with 6z - 18z which is -12z So...
\[(18-12z)\div3 = 18\]
Now we isolate Z by muliplying each side by 3
\[18-12z = 54\]
Now we subtract 18 and divide by -12
\[-12z =36\]
And divide each side by -12
\[z=-3\]

Now that we have Z we can put it into the equation
\[3y-6z=18\]
to solve for Y
So...
\[3y-6(-3) =18\]
Now...
\[3y+18=18\]
So to isolate Y we subtract 18 from each side
\[3y = 0\]
So by the look of our equation is seems Y =0

So now we know X =0, Y = 0 and Z = -3
Plugging in our values The left side should equal the right side
\[9(0) +3 (0)-6(-3) =18\]
\[-6(-3) =18\]
\[18 = 18\]

Hope this helped ^.^