Question

find the derivative of the function using chain rule:
y=xe^-kx

Answer 1

use product rule. y'= x(e^-kx)(-k) + (e^-kx)

Answer 2

I don't understand

Answer 3

i mean i know that i have to use product and chain rule but i don't know how u got that

Answer 4

f(x)=x, g(x)=e^-kx. so f'(x)=1 and g'(x)=(-k)e^-kx.

Answer 5

for g'(x) how did u get that

Answer 6

i mean y did u put -k infront

Answer 7

derivative of e^x is e^x. but u have e^-kx. so you have multiply e^(-kx) by derivative of (-kx) by the chain rule. derivative of (-kx) is -k since k is a constant.

Answer 8

thank u :)