Some steps to construct an angle MNT congruent to angle PQR are listed below. Step 3 is not listed. Step 1 - Use a compass to draw an arc from point Q which intersects the side PQ at point A and the side QR at point B. Step 2 - Draw a segment NT and use the same width of the compass to draw an arc from point N which intersects the segment NT at a point X. Step 3 - Step 4 - Join points N and Y using a straightedge.
Which statement describes step 3 correctly? Maintaining the same width of the compass as BQ, draw and arc from point X such that it intersects the arc drawn from N in a point Y. Use the same width of the compass as the width of NX and draw an arc from point X such that it intersects the arc drawn from N in a point Y. Use the same width of the compass as AQ and draw an arc from point X which intersects the arc drawn from N in a point Y. Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y.
Here is one person's idea on copying an angle. Let's see if that person's third step matches what might be the third step in the posted problem.
I don't get what that person was trying to do...
Copying an angle and constructing an angle congruent to a given angle are the same thing.
So then my answer would be "Use the same width of the compass as the width of NX and draw an arc from point X such that it intersects the arc drawn from N in a point Y."
No. You are copying angle PQR so you would want to get the width from A to B on the compass and mark it off on the arc of the angle you are constructing. So, which option is that?
What is your best guess?
Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y.?
That's what I got - that last option.
Thanks!
Glad to help.
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