Question

Which statement describes the graph of the equation
x^2+y^2+4x-6y-3=0?
A) A hyperbola with center (-2,3) and vertices (4,-3) and (-4,3)
B) a hyperbola with center (-2, 3) and vertices (2,-3) and (3,-2)
C) a circle with center (-2,3) and radius 8
D) a circle with center (-2,3) and radius 4

Answer 1

@sparky16
try to write the equation as
(x^2+4x) + (y^2-6y) -3 = 0
now can u make the perfect squares?

Answer 2

OR can u write x^2 + 4x in the form of (x + some constant value)^2 ???????

Answer 3

so I got down to this
(x+2)^2+(y-3)^2=11
where do I go from here?

Answer 4

u r going to get
(x+2)^2 + (y-3)^2 = 16

Answer 5

oh yes your right it equals 16

Answer 6

now what

Answer 7

the result we get is equation of circle
equation of circle is
(x-a)^2 + (y-b)^2 = r^2
here 'r' is the radius of the circle and 'a' and 'b' are coordinates of center.

Answer 8

so its d?

Answer 9

yup