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What is the solution to the equation 5^x=17 ?
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xlog5 =log17
With \[a^b=c <> \log(a^b)=\log(c)\] Then use \[\log(a^b)=b \log(a)\] Gives \[b \log(a)=\log(c)\] \[b=\frac{\log(c)}{\log(a)}\]
would it be ... \[\log_{10} 17+\log_{10} 5\] or \[\frac{ \log_{10}17 }{ \log_{10} 5 }\]
these are the answer choices..
Yes for\[\frac{ \log_{10}17 }{ \log_{10} 5 }\]
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\[\log(x)=\log_{10}(x)\]
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