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Mathematics 20 Online
OpenStudy (anonymous):

help http://prntscr.com/zm80f

OpenStudy (anonymous):

answer is A is it right

OpenStudy (mertsj):

Angle R is an inscribed angle. It is 1/2 of its arc. So if angle R is 23, its arc is 46. So arc NQ is 46. Angle O has the same arc but angle O is a central angle. Central angles are equal to their arcs. So what is angle O?

OpenStudy (anonymous):

46

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

http://prntscr.com/zm8ft

OpenStudy (anonymous):

iam sure its option D

OpenStudy (mertsj):

Yes. D

OpenStudy (anonymous):

http://prntscr.com/zm9b5

OpenStudy (anonymous):

its either A or B

OpenStudy (mertsj):

A

OpenStudy (anonymous):

http://prntscr.com/zm9lu

OpenStudy (mertsj):

Did you use the Pythagorean Theorem to find BC?

OpenStudy (anonymous):

we have been only given one side ?

OpenStudy (mertsj):

OB=18 OB is the radius. The radius is given. OC = 13 That is another side. There are two sides given.

OpenStudy (anonymous):

so its C

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

http://prntscr.com/zm9tl

OpenStudy (anonymous):

i tried calculating i got A

OpenStudy (mertsj):

Look at triangle AOB. Angle O is 85. Angles A andangle B are equal because the triangle is isosceles. So Angle A + Angle B + 85 = 180 But Angle A and Angle B are equal so Angle A + Angle A + 85 = 180

OpenStudy (anonymous):

95

OpenStudy (mertsj):

Does 95+95+85 = 180 ?????

OpenStudy (anonymous):

47.5

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

http://prntscr.com/zmccu

OpenStudy (mertsj):

The theorem is: CD^2=BC(BC+AB)

OpenStudy (anonymous):

so B

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

A parallelogram has sides measuring 23.8 m and 35.3 m. The height corresponding to the 23.8-m base is 9.9 m. Find the height, to the nearest tenth of a meter, corresponding to the 35.3-m base. A. 8317.4 m B. 14.7 m C. 6.7 m

OpenStudy (mertsj):

The area of the parallelogram is constant no matter which base and height is used. So 23.8(9.9)=35.3(h)

OpenStudy (anonymous):

C

OpenStudy (anonymous):

http://prntscr.com/zmf1g

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

http://prntscr.com/zmf1g

OpenStudy (anonymous):

merts this one is confusing

OpenStudy (mertsj):

There are 64 squares in all. It is hard to count but I counted twice and I got 39 squares that are unshaded. What did you get?

OpenStudy (anonymous):

24 shaded ones

OpenStudy (mertsj):

So that would be 40 unshaded so the probability of unshaded is 40/64=5/8

OpenStudy (anonymous):

The area of a regular octagon is 35 cm2. What is the area of a regular octagon with sides five times as long? A. 625 cm2 B. 875 cm2 C. 175 cm2 D. 245 cm2

OpenStudy (anonymous):

i calculated i got the answer D

OpenStudy (mertsj):

Multiply 35 by 25

OpenStudy (anonymous):

i multiplied 35 by 5

OpenStudy (mertsj):

If you multiply the side by 2, the area will be 2^2 times as big. If you multiply the side by 3, the area will be 3^2 times as big. If you multiply the side by 4, the area will be 4^2 times as big. If you multiply the side by 5, the area will be 5^2 times as big. Try it with a rectangle: |dw:1365354632191:dw|

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