Question

Limits.

Answer 1

Yes.

Answer 2

Show that \[\lim_{x \rightarrow 0} \sin \frac{ 1 }{ x }\] does not exists .

Answer 3

try taking the limit as x aproaches zero from the left and then the right and where that gets you

Answer 4

it gives you sin of infinity...how do i solve that ..??

Answer 5

for both of them

Answer 6

yes one come out to be -lim of sin (infinity) and other is lim sin of infinity

Answer 7

is that dash a negative sin

Answer 8

yes

Answer 9

ok so the funciton is trending toward neg. infinity on the left and pos. infinity on the right

Answer 10

actually sin of both....

Answer 11

Ok then how about using L'Hopital's rule

Answer 12

ok i'll try that way..

Answer 13

Once you take the derivitive, try taking the limit from the left and right. If that does not work, I will try to look up some other tricks we can use

Answer 14

it comes out to be more weird ...like cos of infinity and all..:/ ..please there should be an easy way out..

Answer 15

as x goes to zero, 1/x goes to infinity, then let 1/x = u. sin(u) as u goes to infinity does not exist because the values oscillate between -1 and 1.

Answer 16

so are you saying we cant determine the value ..

Answer 17

the limit does not exist.

Answer 18

u is tending towards infinty not sinu ...:/