Question

Help, please. What is the product of

Answer 1

Can anyone please help me?

Answer 2

Sorry here is the 2nd part of the problem. They should have a . between them

Answer 3

Are you multiplying these equations together?

Answer 4

I think so it has the first problem listed then what looks like period . then the second problem I sent.

Answer 5

Ok the period is another representation of multiplication :P So when multiplying fractions we multiply the first numerator by the second numerator and the first denominator by the second denominator. But by the looks of the two equations they can be factored

Do you understand so far?

Answer 6

yes it is
yes so far

Answer 7

\[\frac{ 12p }{ 4m+m^2{} }\times \frac{ m^{2}+2m-8 }{ 6p }\]
so first thing can do is to factor

Answer 8

Ok so this is what is should look like factored and multiplied
\[\frac{ (m+4)(m-2) }{ 6p } \times \frac{ 12p }{ m(4+m) }\]

So do you understand now?

Answer 9

I factored
\[m ^{2} + 2m -8\]to get \[(m+4) (m-2)\]

Answer 10

so the final answer is what?

Answer 11

Are you working out of a textbook?? if you are what is the answer??

Answer 12

I was trying to figure out how to type some of the symbols in the answer choices. No not working out of a textbook.

Answer 13

Here are the choices:

2(m -2)/m, m ≠ −4, 0 and p ≠ 0

m(m-2)/72p2, p ≠ 0

m(m-2)/72p, m ≠ −4, 0 and p ≠ 0

2(m-2)/mp, m ≠ −4, 0 and p ≠ 0

Answer 14

Well the solution in the first one do you want to know why?

Answer 15

yes please

Answer 16

ok So working with the equation
\[\frac{ (m+4)(m-2) }{ 6p }\times \frac{ 12p }{ m(4+m) }\]
By multiplying them we get...
\[\frac{ 12p(m+4)(m+2) }{ 6p(m(m+4)) }\]
Do you agree??

Answer 17

yes

Answer 18

thank you for explaing it

Answer 19

You're welcome :P I guess :)