For a particular reaction, ΔH = -29 kJ and ΔS = -88 J/K. Assume that ΔH and ΔS do not vary with temperature.
(a) At what temperature will the reaction have ΔG = 0?
K
(b) If T is increased from that in part (a), will the reaction be spontaneous or nonspontaneous?
spontaneous
nonspontaneous

Question

For a particular reaction, ΔH = -29 kJ and ΔS = -88 J/K. Assume that ΔH and ΔS do not vary with temperature.
(a) At what temperature will the reaction have ΔG = 0?
   K 
(b) If T is increased from that in part (a), will the reaction be spontaneous or nonspontaneous?
spontaneous
nonspontaneous

anonymous · Answer

It is simple
for deltaG=0;
deltaH =-Tdelta S
29000=88 xT
hence T=329.54K
b) spontaneous