write tan70-tan30/1-tan70tan30 as a function of a single angle, do not evaluate

Question

yrelhan4 · Answer

Hmm. are you sure this is the question? 
It would be easy if there's a plus sign in the denominator or the numerator? :P

anonymous · Answer

yes this is the question and i know trust me but unfortunately this is the question

yrelhan4 · Answer

I would have to think. Not in the mind frame. Sorry.

anonymous · Answer

haha its okay

anonymous · Answer

you think i can use the sum and difference formula for this

anonymous · Answer

I have no idea......I was thinking just as yrelhan4.......

anonymous · Answer

ya but i was thinking maybe we use the tan(u+-v)

anonymous · Answer

yes.....that is true....let's try that and see what we would get.....

anonymous · Answer

i mean wouldn't i get tan(70+30)

anonymous · Answer

i mean i know it looks easy but i dont think its that easy idk

anonymous · Answer

i am on it.....

anonymous · Answer

$$\tan(u+v)=tanu+tanv/1-tanutanv$$

anonymous · Answer

yes....that expansion of tan is right...

anonymous · Answer

ya so i think thats the answer because the questions says do not evaluate

anonymous · Answer

if that should be the answer, the numerator should be +

anonymous · Answer

no it doesn't need to be cuz look at the expansion it has a negative in the numerator

anonymous · Answer

i am getting confused.....

anonymous · Answer

haha its okay

anonymous · Answer

hold on.....i am trying it...would post it

anonymous · Answer

$$\frac{ \tan70-\tan30 }{ 1-\tan70\tan30 }=\frac{ -(\tan-70+\tan30) }{ 1-\tan70\tan30 }$$

anonymous · Answer

i am not sure. it  may contain mistakes.....i just want to give you a clue....