Mathematics
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OpenStudy (anonymous):
Using the following triangle, what is the cosecant of angle B?
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jimthompson5910 (jim_thompson5910):
If we have this basic right triangle
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
then cosecant of angle B is
csc(B) = hypotenuse/opposite
OpenStudy (anonymous):
c/a , c/b, b/a ,a/b ?
jimthompson5910 (jim_thompson5910):
what's the side opposite of angle B?
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jimthompson5910 (jim_thompson5910):
a?
b?
c?
OpenStudy (anonymous):
c?
jimthompson5910 (jim_thompson5910):
no, side b is opposite angle B
OpenStudy (anonymous):
so b/a
jimthompson5910 (jim_thompson5910):
c is touching angle B and is part of angle B, so c is out
c is actually the hypotenuse
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jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
csc(B) = hypotenuse/opposite
csc(B) = c/b
jimthompson5910 (jim_thompson5910):
that's all you're doing really
OpenStudy (anonymous):
so for cotangent of angle A?
would it be b/a ?
jimthompson5910 (jim_thompson5910):
very good
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OpenStudy (anonymous):
Using the following triangle, what is the cotangent of angle A? ?
jimthompson5910 (jim_thompson5910):
you just asked that?
OpenStudy (anonymous):
cotangent < a little bit diffrent
jimthompson5910 (jim_thompson5910):
oh this is for a different triangle?
OpenStudy (anonymous):
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jimthompson5910 (jim_thompson5910):
it would be b/a like you got last time
OpenStudy (anonymous):
oh ok it confused me a little
jimthompson5910 (jim_thompson5910):
ah i see
OpenStudy (anonymous):
Find the sine of angle A.
jimthompson5910 (jim_thompson5910):
sin(A) = opposite/hypotenuse
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
sin(A) = opposite/hypotenuse
sin(A) = 12/13
OpenStudy (anonymous):
12/13 ?
OpenStudy (anonymous):
ok got it
jimthompson5910 (jim_thompson5910):
good
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OpenStudy (anonymous):
Find the tangent of angle Y
jimthompson5910 (jim_thompson5910):
you got what?
OpenStudy (anonymous):
c/b ?
jimthompson5910 (jim_thompson5910):
use the triangle you just posted
OpenStudy (anonymous):
i mrean 6/10
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OpenStudy (anonymous):
mean*
jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
that's not correct
OpenStudy (anonymous):
6/8
OpenStudy (anonymous):
simplified = 3/4
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jimthompson5910 (jim_thompson5910):
perfect
jimthompson5910 (jim_thompson5910):
tan(Y) = 3/4
OpenStudy (anonymous):
Find the cosine of angle Z.?
jimthompson5910 (jim_thompson5910):
what did you get
OpenStudy (anonymous):
3/5 ?
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jimthompson5910 (jim_thompson5910):
nailed it
OpenStudy (anonymous):
cFind the secant of angle Z. 4/5 ?
jimthompson5910 (jim_thompson5910):
to find the secant of Z, you just flip the fraction you got for the cosine of Z
jimthompson5910 (jim_thompson5910):
this is because if
cos(Z) = a/b
then
sec(Z) = b/a
OpenStudy (anonymous):
5/3 ?
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jimthompson5910 (jim_thompson5910):
good
OpenStudy (anonymous):
Find the cosine of angle A
OpenStudy (anonymous):
OpenStudy (anonymous):
12/13?
jimthompson5910 (jim_thompson5910):
that would be cos(B) since the 12 is adjacent to angle B
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jimthompson5910 (jim_thompson5910):
but you want cos(A)
OpenStudy (anonymous):
5/12 ?
jimthompson5910 (jim_thompson5910):
better
jimthompson5910 (jim_thompson5910):
oh wait, mixed up the terms
it should be 5/13
jimthompson5910 (jim_thompson5910):
cosine is adjacent over hypotenuse
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OpenStudy (anonymous):
Find the cotangent of angle Z.
OpenStudy (anonymous):
fpr the previous one would be 4/3 ?
OpenStudy (anonymous):
for *
jimthompson5910 (jim_thompson5910):
post the pic again
jimthompson5910 (jim_thompson5910):
there's too many of them lol
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OpenStudy (anonymous):
jimthompson5910 (jim_thompson5910):
and you got what?
OpenStudy (anonymous):
4/3
jimthompson5910 (jim_thompson5910):
you got it flipped somehow
jimthompson5910 (jim_thompson5910):
cot(Z) = 3/4
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jimthompson5910 (jim_thompson5910):
remember that cot(Z) = adj/opp
adj = 3
opp = 4
OpenStudy (anonymous):
ohh okay got it
jimthompson5910 (jim_thompson5910):
and it's all in reference to whatever angle you're working with
so if you go from Z to Y, then the adj and opp will switch
OpenStudy (anonymous):
ok got it thanks
jimthompson5910 (jim_thompson5910):
np