Question

definite integrals?
integral of (x^2-4x+4)^1/2 dx?

Answer 1

luckily x^2 - 4x + 4 = (x-2)^2

Answer 2

\[\int\limits_{0}^{2}\sqrt{x^2-4x+4}dx\]

Answer 3

so what you effectively have is sqrt( (x-2)^2 )

Answer 4

i tried it that way, but i got it wrong

Answer 5

sqrt( (x-2)^2 ) = |x-2|

Answer 6

oh absolute value

Answer 7

so you want the area under the curve from x = 0 to x = 2

Answer 8

the graph looks like this

Answer 9

and you want this area