A baseball team plays in a stadium that holds 51,000 spectators. With ticket prices at $10, the average attendance had been 38,000. When ticket prices were lowered to $8, the average attendance rose to 42,000. Find the demand function (price p as a function of attendance x), assuming it to be linear??

Question

anonymous · Answer

I just need to find the equation. i keep getting this and its wrong  : p = -1000 x+ 59,000

jim_thompson5910 · Answer

With ticket prices at $10, the average attendance had been 38,000

means

x = 38000
p = 10


giving you one point (38000, 10)

jim_thompson5910 · Answer

When ticket prices were lowered to $8, the average attendance rose to 42,000

means

x = 42000
p = 8

so another point is (42000, 8)

jim_thompson5910 · Answer

now find the slope of the line through those two points

anonymous · Answer

yes and i get p = -1000 x+ 59,000

anonymous · Answer

it says its wrong

jim_thompson5910 · Answer

the slope is way to big

jim_thompson5910 · Answer

m = (y2-y1)/(x2-x1)



m = ( 8- 10)/(42000-38000)



m = -2/4000



m = -1/2000



So the slope of the line that passes through the two points is  -1/2000

anonymous · Answer

and how u find b?

jim_thompson5910 · Answer

y = mx + b

y = (-1/2000)x + b

38000 = (-1/2000)(10) + b

solve for b

anonymous · Answer

im getting b=7600001/200 n i believe thats way too big

jim_thompson5910 · Answer

38000 = (-1/2000)(10) + b


38000 = -1/200 + b


38000 + 1/200 = b


7600000/200 + 1/200 = b


7600001/200 = b


b = 7600001/200


b = 38000.005

anonymous · Answer

so y=(-1/2000)x 
+760001/200?

anonymous · Answer

it says its wrong :(

jim_thompson5910 · Answer

try using decimal form instead of fraction form

anonymous · Answer

(a) Find the demand function (price p as a function of attendance x), assuming it to be linear.

anonymous · Answer

thats the actual question

jim_thompson5910 · Answer

i know

jim_thompson5910 · Answer

maybe you entered the fraction in wrong, try it in decimal form

anonymous · Answer

yea it doesn't let me put in decimals

jim_thompson5910 · Answer

ok post a screenshot of what you're inputting

anonymous · Answer

sec

jim_thompson5910 · Answer

k

anonymous · Answer

attachment

jim_thompson5910 · Answer

the numbers are different from what you gave me

anonymous · Answer

yea I just noticed wow.. im sorry

jim_thompson5910 · Answer

it's fine, use the same idea just with these correct values

anonymous · Answer

Thank you

jim_thompson5910 · Answer

yw