Question

I have the answer can someone please check me
the volume of a cube is decreasing at a rate of 0.24 ft^3/min. What is the rate of change of the side length when the side length are 2 feet.

Answer 1

V = s^3

dV/dt = 3s^2*ds/dt

-0.24 = 3*2^2*ds/dt

-0.24 = 12*ds/dt

keep going to solve for ds/dt

Answer 2

I got -12.24

Answer 3

is that right

Answer 4

or -.02

Answer 5

-0.24 = 12*ds/dt

-0.24/12 = ds/dt

-0.02 = ds/dt

ds/dt = -0.02

Answer 6

ok I subtracted instead of divided

Answer 7

so the side is changing at a rate of -0.02 ft/min when s = 2 ft

Answer 8

so the .02 is the rate of change

Answer 9

yes a decrease of 0.02 ft/min

Answer 10

what do you mean decrease

Answer 11

I guess I should say that the side is decreasing at a rate of 0.02 ft/min when the side length is 2 ft

Answer 12

do you mean -.02

Answer 13

rate of change = -0.02 ft/min

is the same as saying "the side is decreasing at a rate of 0.02 ft/min"

so yes

Answer 14

decrease means gets smaller