Question

help please!

how do I solve this equation by completing the square?

2x^2 - 2x -7 = 0


I can do it if there is no coefficient for the x^2 :(

Answer 1

you need to divide by 2

Answer 2

\[2x^2-2x=7\]
\[x^2-x=\frac{7}{2}\]
\[(x-1)^2=\frac{7}{2}+1=\frac{9}{2}\]
\[x-1=\pm\sqrt{\frac{9}{2}}=\pm\frac{3}{\sqrt{2}}\]

Answer 3

finish by adding 1 to both sides to solve for \(x\)

Answer 4

oh okay so this technique is still completing the square?

Answer 5

thanks... will study this thank you :D