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find the unit tangent vector to the curve r(t)=((t^-1)+t),((t^-1)+t),-1) at t=1
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Find \(\mathbf{r}'(t)\) Can you do it?
The Unit Tangent Vector is, obviously, a unit vector and it is defined as: \[=\frac{ r \prime (t) }{ \left| r \prime (t) \right| }\]
\(\mathbf{r}'(t)\) is the tangent vector. To make it unit, divide by magnitude \[ \mathbf{\tau}(t) = \frac{\mathbf{r}'(t)}{\|\mathbf{r}'(t)\|} \]
ok thanks i think i can do this now
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