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4/x + 6/x+9 = (* / they are fractions)
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solve g^x+2 = (1/27) ^x=12
log2(72)-2log2(3)
4/x + 6/x+9 10x +36 / x(x + 9)
evaluate a) 16^1.25 b) 125^4/3 c) 8^2/3 x 4^5/2
a) 16^1.25 16^1 1/4 16^5/4 2^5 = 32
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understand?
i dont understand how you got that
u agree that .25 = 1/4 ?
ya
\[16^{1.25}=16^{5/4}\] does this make sense?
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yes
\[(2^{4})^{\frac{ 5 }{ 4 }}\] understand? cause 16 = 2^4
yes thank you so much!
do b and ill correct if for u :) cool?
125^4/3 (5^4)^1.25 this is all i can get?
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125 = 5^3 try it now :)
im still confused
\[125^{4/3}\]\[(5^{3})^{\frac{ 4 }{ 3 }}\] better?
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