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OpenStudy (anonymous):

Graphing square root functions, how do you know if the equation will be less than or equal to, or greater than or equal to?

OpenStudy (anonymous):

can you give an example of what you mean? im not sure I understand your'e question

OpenStudy (anonymous):

\[y=4/7\sqrt{18-x}\] I am trying to find the domain of this function. I know I use teh square toot part, btu Im not sure how to find out if it would be greater than or equal to, or less than or equal to.

OpenStudy (anonymous):

ok. i got you

OpenStudy (anonymous):

so, when we write the square root symbol, we are only asking for what are known as real numbers. there is something called "imaginary numbers." I know it sounds like im making this up but im not. we get imaginary number when we try to take the square root of a negative number.

OpenStudy (anonymous):

because these numbers aren't real we try to only take the square root of positive numbers (including zero)

OpenStudy (anonymous):

Ok, I understand that.

OpenStudy (anonymous):

so, the first thing we need to is make sure the number under the square root is not negative.

OpenStudy (anonymous):

have you ever heard the term "undefined"?

OpenStudy (anonymous):

Yes.

OpenStudy (amistre64):

is that sqrt in the denominator as well?

OpenStudy (anonymous):

No the square root isnt, teh equation is a fraction and a sqaure root but they are separate.

OpenStudy (anonymous):

so when something is undefined it means that the math just doesn't make sense. one of most common examples of undefined things is when you have 0 as a denominator

OpenStudy (amistre64):

just making sure :) if it was under, then sqrt(0) would have to be weeded out as well

OpenStudy (anonymous):

exactly

OpenStudy (amistre64):

as a rule of thumb for "real" solutions; we have a few rules, no dividing by zero, no negative sqrts, and keep you logs positive

OpenStudy (amistre64):

well, no negative even roots, sqrt is even since it implies a 2

OpenStudy (anonymous):

Ok, I see how all of that works. But Im still confused about how to find the domain of a square root function.

OpenStudy (amistre64):

so for this domain (all valid x values) we want the sqrt arguement (18-x) to be greater than or equal to zero.; therefore you would just need to solve:\[18-x \ge0\]

OpenStudy (amistre64):

add x to both sides, what do you end up with?

OpenStudy (anonymous):

\[18\ge x\]

OpenStudy (amistre64):

good, and notice that since "x" is on the smaller end of the ">", we read it as; x is smaller than or equal to 18

OpenStudy (anonymous):

Ok, that makes sense. Thank you :)

OpenStudy (amistre64):

youre welcome, and good luck :)

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