find the number of steel ball bearings, each of diametre 0.7 cm,that can be made from 1 kg of steel given that 1cm cube of steel weighs 7.85g
Step 1, the determine volume of the 1kg steel.
hello please answer
Step 1: The volume. We're doing it step by step. Right?
tell me the equaions
Alright. If you insist, I solve it for you. Step 1: I take the volume of the steel ball. The diameter is 0.7 cm, thus the radius is 0.35 cm. The volume is given by( 4/3)*pi*r^3
where r is the radius.
step 2: I have the density, I multiply the density by the volume. That gives me mass of ONE small steel ball.
Step 3: I divide the mass of ONE steel ball by the total mass of steel I have, in this case, being 1 kg. I take the greatest integer function of it. THAT gives me the solution.
i dont understand
Did you try puttin in the values and following the procedure?
I mean, any kind of help is useless if you're not willing to give it a listen and expect the answer to just come to you.
i dont understand step 3
See, you got the mass by step 2. That is (assume) m. Now, the value of m is in grams. Right?
please show me the equation i dont understand
Did you get the value of mass by step 2?
Please, cooperate if you want to understand.
1.40515
That's a value in grams. Now, What I did in step 3 is:- 1kg=1000 g of steel. That I have. I divided it:- 1000g/mass of 1 ball.
then
That gives you a value. Which is the number of balls. I assume it comes in a decimal number?
no the answer is 790
709
brb, lost my calc.
Volume= 0.179 cm^3
step 2: mass comes as 1.409 g
step 3: 1000/1.409=709.312 I take the greatest integer function: 709
thanks
No problems, next time, please participate in problem solving. =)
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