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Mathematics 7 Online
OpenStudy (anonymous):

Please anyone help and explain :(

OpenStudy (anonymous):

OpenStudy (anonymous):

We solved plenty many questions like that today. Didn't we?

OpenStudy (anonymous):

I simplified it to \[(4 + i \sqrt{3}) x (4-i \sqrt{3})\]

OpenStudy (anonymous):

Yes but I am not sure if I am doing them correctly. it the one I typed ^ correct?

OpenStudy (anonymous):

ye weren't supposed to do that, exactly. see, let's forget that imaginary thing here. We have a=4 and b=sqrt-3 There's 'aight?

OpenStudy (anonymous):

now, you know (a+b)^2?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

well, put the values 4 and i(sqrt(3)) in there... what does that give you?

OpenStudy (anonymous):

\[4^{2} + 2 (4 x i \sqrt{3}) + (i \sqrt{3}) ^{2}\]

OpenStudy (anonymous):

is it correct?

OpenStudy (anonymous):

Yes, indeed it is! Now, the solution will come in to be...

OpenStudy (anonymous):

\[16 + 8 + 2 -\sqrt{3} - \sqrt{3}\]

OpenStudy (anonymous):

is this correct?

OpenStudy (anonymous):

@NeetziD

OpenStudy (anonymous):

It's 16 - 8(sqrt3) i -3 actually. You made a mistake there, I guess. Just stop writing x instead of multiplication...

OpenStudy (anonymous):

sorry. would the answer be 13-8i(sqrt3)

OpenStudy (anonymous):

Yes. There you go, solved! Practice a few more questions on your own. You'll get it.

OpenStudy (anonymous):

Thank you so much!!!

OpenStudy (anonymous):

YW. :)

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