Question

-3|x-2|+10=12


x = 1 and x = 5

x = −1 and x = −5

x = −9 and x = 3

No Solution

Answer 1

@AravindG HELP ME PLEASE STEP BY STEP

Answer 2

\[-3|x-2|=2\]
now we square this..
the only way to get rid of the absoute sign is to square it

Answer 3

or make two equations out of it.

Answer 4

ok wait spuare the hole thing

Answer 5

yes see the above simplified orm

Answer 6

\[\left[-3|x-2|\right]^2=2^2\]

Answer 7

ok wat about the + 10

Answer 8

I subtracted it from the two sides

Answer 9

notice that the right side became 12-10=2

Answer 10

where did u get the 12 frm

Answer 11

@electrokid

Answer 12

where did u get the 12 from

Answer 13

\[-3|x-2|+10=12\qquad\text{....given}\\
\qquad\qquad-10\quad-10
\]

Answer 14

ok srry im just learning this ok and then gives u this


[−3|x−2|]^2=2^2

Answer 15

that is ok.
well, this first gives
\[-3|x-2|=2\]
so, we the square it like you just wrote above

Answer 16

yes

Answer 17

\[(-3)^2(x-2)^2=(2^2)\]
notice that the absolute sign has disappeared

Answer 18

so 9*2x-4=4

Answer 19

or to avoid squaring, you can remove the abolute sign in two ways......
\[-3|x-2|=2\implies|x-2|=-{3\over2}\]

Answer 20

how did u get 3/2

Answer 21

my bad... \[\Large{|x-2|=\color{red}{-}{2\over3}}\]

Answer 22

ooh its ok but how did u get that

Answer 23

divide the two sides by "3"

Answer 24

ok

Answer 25

\[{-3|x-2|\over-3}={2\over-3}\]

Answer 26

this gives the above form..
now, by definition of ABSOLUTE value, can it ever become negative?

Answer 27

HEY STOP STOP STOP I WROTE THE PROBLEM DWN WRONG
SRRY

THIS IS THE PROBLEM −3|2x + 6| = −12

Answer 28

ok...
you mean no "10" in there?

Answer 29

yea

Answer 30

this is so much different than what you first asked for

Answer 31

ok.. proceeding similarly, get the absolute quantity on its own...

Answer 32

ik b/c its 2 differnt problems in one

Answer 33

\[\Large{-3|2x-6|=-12\\\text{divide both sides by -3}\\
|2x-6|=4\\\text{to get rid of absolute sign, we get two possible answers}\\\;\\
2x-6=4\qquad{\rm AND}\qquad2x-6=-4\\
2x=4+6\qquad\qquad\qquad2x=-4+6\\
2x=10\qquad\qquad\qquad\quad2x=2\\
\boxed{x=5}\qquad\qquad\qquad\quad\boxed{x=1}}
\]

Answer 34

check, plug in "x=" those numbers in the given problem on the left side. That should give you the right side.

Answer 35

thanks

Answer 36

did you understand?

Answer 37

yes