Since current is v/r is you had a 50 ohm and 10 ohm resistor, which would have most current? Show work.
I know it is a physics problem but it requires the math and I need the steps
@Jonask @jhonyy9 @robtobey
v is voltage and r is resistance
you can pick any value for v and use that value for calculating the current in the two resistors...
Well, if it was a 9V battery I=9/10=.9 I=9/50=.18 But I thought the more resistance the less current...
@kausarsalley
it depends how you connect them in 1 series 2 parrallel 3 seperate circuit with same voltage
This is in parallel
case 1 they have the same current case 2 smaller resistor has more current since we are using \[\frac{ 1 }{ R_p }=\frac{ 1 }{ R_1 }+\frac{ 1 }{ R_2 }\] current is split accorind to their ratio jus imagine a traffic with lots of cars(resistance) and a one without current takes the easy way out ,smaller traffic(resistanvce)
The attatchment has the problem and the key said B is that right
yes....the more the resistance, the lesser the current
yes
I=9/10=.9 I=9/50=.18
just as demonstrated in your calculation....
THanks!
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