Solve the system of equations. Show your work. x + 2y = 5 3x + 2y = 17 im still beyond confused... :l
lol no u will show me ur work :P ok lets use the substitution method, familiar with that one?
Yea
cool can u do that now then? or would u like me to start u off?
i can probably do it now.. thanks
What you have to do is just eliminate the "y" just by subtracting those two equations.
if u want u can show us ur working and we will correct it or show us ur answers and we will confirm them :)
lol, that's a better idea @HawkCrimson
the answer i got for the first equation is y = 2.5 + -0.5x
Im still new at this
that's right
ok and y = 8.5 + -1.5x is what i got for the second one
umm u want to have exact answers for y and x
yep that's right
like y = 5 and x=3
so wat u did didnt answer the question.. so u know how to solve for y and x?
it's still the same, but yeah you should put it as \[\frac{ 5 }{ 2 }\]and all the rest in fractions
Divide both sides by two. right?
yes @mirandabell902
ok
y = 5/2 for the first and y = 5/8 for the second one, right?
both of them r supposed to have the same y and x value
ok ill do it with u cause idk wat u were doing before and i dont know how u got those two equations but ill show u how to do it by substitution :)
first take the 1st equation x + 2y = 5 and make y or x the subject of the formula (it doesnt matter)
okay
wat did u get?
y=5
calm down, one step ata time and i didnt get that.. just rearrange the formula for me and show me how it looks with x or y being the subject of the formula.
y=2+5
x + 2y = 5 x = 5 - 2y or y = (5-x)/2 that is wat i wanted, understand?
yes
so choose any one lol
x = 5 - 2y
The easiest way is just subtract. that way, it cancels 2y in the first equation and 2y in the secnd equation. then, you'll get the x
yea..nice to know @Lynncake .. as i was saying @mirandabell902 :P
\[-\left(\begin{matrix}x+2y=1 \\ 2x+2y=1\end{matrix}\right)\]\[-x=0 \rightarrow x=0\]
or u can interupt me again...sure.
:D sorry, ok go on
lol even im confused now D:
eh just show her the subtraction method lol
but we should be confusing her with showing her two methods at the same time lol
yeah you're right, but just finish yours :D @HawkCrimson
i have to go bye. u do the rest and plus she isnt even replying..
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