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Mathematics 22 Online
OpenStudy (anonymous):

A bag contains 7 green marbles, 9 red marbles, 10 orange marbles, 5 brown marbles, and 10 blue marbles. You choose a marble, replace it, and choose again. Find P(red, then blue).

OpenStudy (anonymous):

see, U hv 2 choose 1 red marble and no. of ways of doing it is 7C1. Then u hv to choose a blue marble which can be done in 10C1 ways. Total no. of ways of choosing a marble of any colour is 41C1. So ur P={(7C1)/(41C1)}*{(10C1)/(41C1)}

OpenStudy (anonymous):

is it 77/164?

OpenStudy (anonymous):

it is 70/1681

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