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Mathematics 18 Online
OpenStudy (anonymous):

6. A kite has diagonals 5.3 ft and 6 ft. What is the area of the kite? (1 point)5.65 ft² 15.9 ft² 31.8 ft² 22.6 ft²

OpenStudy (anonymous):

C?

OpenStudy (mathstudent55):

The area of a kite is half the product of the diagonals.

OpenStudy (anonymous):

i did 5.3*6

OpenStudy (mathstudent55):

|dw:1365453353838:dw|

OpenStudy (mathstudent55):

Notice in the kite above that the lengths of the diagonals are the same as the lengths of the length and width of the rectangle. If you multiply the lengths of the diagonals, you get the area of the rectangle. Now notice that for each triangle inside the kite (for example, 1b, 2b, ...) there is a corresponding congruent triangle inside the rectangle but outside the kite (1a, 2a, ...). Therefore, the area of the kite is half the area of the rectangle. Since the area of the rectangle is the product of the length and width of the rectangle, and we saw above that the length and width of the rectangle are the same as the diagonals of the kite, then the area of the kite is half the product of its diagonals.

OpenStudy (anonymous):

D

OpenStudy (anonymous):

@e.mccormick

OpenStudy (anonymous):

I'm very confused

OpenStudy (e.mccormick):

Hi there! It looks like he went over the key parts.

OpenStudy (e.mccormick):

Ah. OK. Well, he was trying to show you how the kite was a bunch of triangles.

OpenStudy (anonymous):

I got C at first but now I'm not sure....

OpenStudy (e.mccormick):

OK. Well, before I look at the answers, you understand the relationship between the area of a rectangle and a triangle?

OpenStudy (anonymous):

No thats what confused me like I get it but i dont't

OpenStudy (mathstudent55):

Forget everything below my first answer. Did you see my first answer which just simply explains how to find the area of a kite? Read it again. It's just below your question C?

OpenStudy (anonymous):

What diagnals or may I say which?

OpenStudy (e.mccormick):

OK. It is one of those underlying principas, bu doing it with the whole kite might have been too much. And C is not right.

OpenStudy (anonymous):

is there a step I did wrong what is the easiest way to do this

OpenStudy (e.mccormick):

Lets try one rectanhle and one triangle.|dw:1365454989511:dw| The area of a rectangle is the Base times the Height. The right triangle is HALF the base times the height. That word, HALF, is very critical in this kite problem.

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