Question

The input work done on a machine is 9.63 × 103 joules, and the output work is 3.0 × 103 joules. What is the percentage efficiency of the machine?

Answer 1

\[\frac{ (3.0 x 10^3) }{ (9.63 x 10^3) } \] This is equal to:
0.312 x 100% = 31.2% efficient

Answer 2

Efficiency is the cocient between the output and the input expresed in percentage. In other words.\[Efficiency=\frac{ W _{output} }{ W _{ input } }=\frac{ 3 \times 10^{3} }{ 9.63 \times 10^{3}} =0.3115264798=31.2 percent\]