graph the original and inverse.
\[y=2x^{2}\]
\[y=\sqrt{x-2}\]
y=2x+6 over 2
@dpaInc
do you know how to obtain the inverse of these functions?
*analytically?
switch the x and y and solve for y... that'll give you the inverse. as far as graphing, you'll need to enter that in your graphing calculator....
umm im not sure do you just do the opposite
for example, let's do the second one you have (since it's easy to solve for the inverse)
\(\large y=\sqrt{x-2} \) switch the x and y: \(\large x=\sqrt{y-2} \) solve for y.... can you do this for me?
i got x+2=y s
no....
\(\large x=\sqrt{y-2} \) \(\large (x)^2=(\sqrt{y-2})^2 \) square both sides \(\large x^2=y-2 \) simplify \(\large x^2+2=y-2+2 \) add 2 to both sides \(\large x^2+2=y \) simplify ok from here?
umm oh my gosh i dont know and after u solve everything then we graph it?
yes... do you have a graphing calculator?
yes but i dont know how to use it lol
here is an excellent online graphing calculator that u can use to graph original: \(\large y = \sqrt{x-2} \) inverse: \(\large y=x^2+2 \) https://www.desmos.com/calculator go ahead and try....
screen shot of the graphs...
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