Question

determine the average rate of change of f(x)=x^4-2x between the given values x=-1,x=3

Answer 1

Do you know it's formula ?

Answer 2

yeah i was tryin to work it out but i dont know what to do with the two x values

Answer 3

\[\Large Average rate of change = \frac{f(x+h)-f(x)}{h}\]
where x=x1 , h= x2-x1
Got it ?

Answer 4

ok let me try it

Answer 5

i got 29 but its telling me its the wrong answer

Answer 6

so for x would be -1 and h would be 4 right

Answer 7

F(x)=x^4-2x . (x1=-1) ,(x2=-2)
Substitute :
\[\Large \frac{(x^4-2x)-(x^4-2x)}{x_{2}-x_{1}}\]
\[\Large \frac{((-2)^4-2(-2))-((-1)^4-2(-1))}{-2-(-1)}\]
The result will be :
-17 .
Sry ,There is lag :s

Answer 8

how did you get negative 2

Answer 9

its the value of x2

Answer 10

i dont know why but it keeps saying thats not the answer ill see what i can do thanks either way

Answer 11

do you think i have to take the derivative first

Answer 12

The rate of change is the first degree of differential

Answer 13

OMG Dang ,Sry i thought that the value of x2 = -2 :OOOOOOOOOOOOOO that is soo weird
I'am sry
Look we will do the same steps but instead of -2 we will put 3 .

Answer 14

okay let me try it

Answer 15

yeah that was it thank you so much :)

Answer 16

Yw,and sry for that i was kinda hyper :P