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Diagonal length of a square is growing at a rate of 20 meters per second. How fast is the are enclosed by the square growing at the instants the area equals 100 squared meters? Walk through please!>.<
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related rate problem?
area of a square with diagonal \(x\) is \[A(x)=\frac{d^2}{2}\] is a start
i mean \[A(x)=\frac{x^2}{2}\]
then take the derivative, get \[A'=xx'\]
you are told \(x'=20\) so this gives \[A'=20x\] then if \(x=100\) you can find \(A'\)
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hope it is more or less clear
After a few tries I got it thanks(:
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