Question

Trigonometry

Answer 1

The value of the trigonometrical expression \[(4\sin2\ 60^o + 3\tan2\ 30^o – 8 \sin45^ocos 45^o) \ is\]

@kropot72

Answer 2

help?/

Answer 3

Just substitute these values:
\[\sin ^{2}60=(\frac{\sqrt{3}}{2})^{2}\]
\[\tan ^{2}30=(\frac{1}{\sqrt{3}})^{2}\]
\[\sin 45=\cos 45=\frac{ \sqrt{2}}{2}\]

Answer 4

I didn't get that

Answer 5

@kropot72

Answer 6

What part didn't you get? You just need to plug in the values that I gave and simplify.

Answer 7

the starting

Answer 8

\[(4\times \frac{3}{4})+\frac{3}{3}-8(\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{2})=?\]

Answer 9

1/2

Answer 10

3 + 1 - 4 = ?
Do you want to know how the exact values for the trig ratios are derived?

Answer 11

yo if u could do that

Answer 12

@Rohangrr , kropot72 basically gave you the answer, his work is spot on. If you follow each of this work from each post, you'll get to the right answer, which, as he/she said in their last response, is 0