What volume of benzene (C6H6), d=0.88 g/mL ,molarmass = 78.11 g/mol is required to produce 1.5 x103 kJ of heat according to the following reaction?

ΔHorxn= -6278kJ

2C6H6(L) + 15 O2(g) → 12CO2(g) 6H2O(g)

so we have
density = .88 g/ mL
mass = c6 h6 78.11 g /mol
q = 1.5 x 10^3 kj
d H = -6278

Question

What volume of benzene (C6H6), d=0.88 g/mL ,molarmass = 78.11 g/mol is required to produce 1.5 x103 kJ of heat according to the following reaction?
 
   ΔHorxn= -6278kJ
 
      2C6H6(L) + 15 O2(g)   → 12CO2(g)  6H2O(g)

so we have 
density = .88 g/  mL
mass = c6 h6 78.11 g /mol
q = 1.5 x 10^3 kj
d H = -6278

anonymous · Answer

I multiplied 78.11 g /mol x 2 mol = 156.22 g C8 H8

156 g of C 8 H8 will produce 6278 kJ of heat, right?