If f(x) is a twice-differentiable function and f’’(c) = 9 at an interior point c of f’s domain, must f have an inflection point at x = c? Explain.
f(x) has an inflection point at x=c if and only if f''(c) = 0 so, what do you think?
Umm idk
what happens when 1) second derivative > 0 -> 2) second derivative < 0 -> 3) second derivative = 0 ->
in > 0 its concave up and < 0 its concave down if its = 0 no concavity or it is a possible inflection point
correct. so thats the answer. look at the third one you said and compare it with the given second derivative.
so yes it does have an inflection point
how? explain your train of thoughts.
never mind i cehcked it doesn't
no solutions exist
the question does not ask for a solution! but an answer to the question and an appropriate explanation
ohh ok so i could say there is no inflection point at x = c because its equal to 0 and we know when it equals to zero there is not concavity?
the question said, f''(c)=9 we know that \(9\ne0\) and that \(9>0\). but for inflexcion point, \(f''(c)\) MUST EQUAL 0 so....
ohh ok
i'm still not getting this
ok, you said that at inflection point, \(f''(x)=0\), right?
yes
good. and what is the given \(f''(x)\)?
its 9
so.... ?
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