Question

Can someone help walk me through this? Separable equations.

Answer 1

\[(1+tany)y' = x^2+1\]

Answer 2

Integrate both sides with respect to \(x\), and notice that \(y'dx = dy\)

Answer 3

So would it be this?
\[\int\limits \frac{ dy }{ 1+tany } = \int\limits (x^2+1)\]

Answer 4

I'm barely learning this so I don't have a real good grasp on the concept yet.

Answer 5

the setup is already separated into ys on one side and xs on the other

Answer 6

no need to divide by 1+tany, unless that was an error in your original post

Answer 7

\[\int\limits (1+tany)~dy = \int\limits (x^2+1)~dx\]

Answer 8

So just integrate this and done?