Question

Find the horizontal asymptote: x^2/x^4-16

Answer 1

the horizontal asymptote is y = zero...

this is because the power of the leading term in the denominator is greater then the power of the leading term in the numerator.

Answer 2

thank you! do you know what the vertical asymptote would be? @campbell_st

Answer 3

yep the vertical asymptotes occur when the denominator is equal to zero... so you need to solve

\[x^4 - 16 = 0\]

which is

\[x^4 = 16\]

so x = -2 and 2

so the vertical asymptotes are at x = -2 and x = 2

Answer 4

that's what I thought...thank you so much! @campbell_st