Question

I've been stuck on these two problems for some time now. About an hour and a half. Attachments below

Answer 1

Sorry if those are hard to see

Answer 2

\[4\sqrt{6}\div \sqrt{30}\]

Answer 3

\[\left( 2\sqrt{5} +3\sqrt{7} \right)^2\]

Answer 4

For an expression \(\frac{\sqrt{x}}{\sqrt{y}}\), you rationalize it by multiplying it with a fraction that its numerator and the denominator is the same as the expression's denominator (i.e \(\frac{\sqrt{y}}{\sqrt{y}}\).

Answer 5

That confuses me. I got this \[\frac{ 4 }{ \sqrt{5} }\]

But I don't know if thats right or how i got it

Answer 6

Like i said, I have been stuck for hours

Answer 7

@HatSimulator Is 4/sqrt{5} the answer to the first question, or the second one?

Also, remember that Wolfram|Alpha is your friend. If you're unsure whether your answer is correct, simply throw the expression into W|A and let it check for you. (No cheating though!)

Answer 8

Okay. And that was the answer to the first question

Answer 9

I used Wolfram:Alpha to do that problem actually

Answer 10

@HatSimulator You shouldn't rely on W|A for your homework unless you're in college. ;)

Yes, your answer is correct for the first question.

Answer 11

But i dont know how i got it.. like via steps. and that was the only time i've ever used it to be honest

Answer 12

@HatSimulator This is where you should start (remember what I mentioned earlier about multiplying with a new fraction)

\(\large{\frac{4\sqrt{6}}{\sqrt{30}}} \times \frac{\sqrt{30}}{\sqrt{30}}\)

Answer 13

Okay, got that part