Question

A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t² + 148t + 30. How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.

9.25 s; 30 ft
4.63 s; 640.5 ft
4.63 s; 1,056.75 ft
4.63 s; 372.25 ft

Answer 1

Hi would anyone mind helping me, thanks in advance :D

Answer 2

are you familiar with derivative?

Answer 3

What is that?
:/

Answer 4

how about the vertex of a parabola?

Answer 5

I've heard of it...

Answer 6

Can I trust you with a name like that... :/ Lol

Answer 7

Oh yeah duhh I know what that is lol

Answer 8

haha :D

Answer 9

So should I just graph the equation...

Answer 10

anyways, if you graphed the equation, where height is the y axis and time is the x axis, it would look some thing like the graph i drew above

Answer 11

Oh alrighty then :)P

Answer 12

Ill goto wolframalpha.com

Answer 13

http://www.wolframalpha.com/

Answer 14

the maximum height would occur at the vertex
this could be solved by finding the derivative and solving for x when its equal to 0

or by solving for the vertex, where x= -b/2a

Answer 15

once you've determine the time when the maximum height occurs, then you substitute the time back into the equation to determine the maximum height

Answer 16

Soo... http://www.wolframalpha.com/input/?i=h+%3D+%E2%80%9316t%C2%B2+%2B+148t+%2B+30

Answer 17

What now?

Answer 18

that would be cheating

Answer 19

How so?

Answer 20

because you didnt solve it out for yourself

anyways the answer is already given to you.... there's nothing more i can say