Question

no

Answer 1

you should show your work in order for us to help you :)
1. Take all variables in the left side and the numbers in the right side separated by = (equation sign) to get the value of the x. Since the exponent of x is 2, there are 2 values of x.
2. In rationalizing, take the opposite sign and don't change anything. \[\frac{ 1 }{ 1+x }*\frac{ 1-x }{ 1-x }\]helps?

Answer 2

I don't get the 2nd one

Answer 3

like 1+x, to find the conjugate just take the opposite sign of + which is -.
So the conjugate of 1+x is 1-x

Answer 4

can you please do the 2nd one for me!!!! Please i don't get it at all..

Answer 5

\[\frac{ 3\sqrt{2} }{ 2\sqrt{3}-5\sqrt{2}}*\frac{ 2\sqrt{3} +5\sqrt{2}}{ 2\sqrt{3}+5\sqrt{2} }\]

Answer 6

Your aim is to make it like \[(a^2-b^2)=(a+b)(a-b)\]

Answer 7

where do i get the a^2 and b^2 and a b

Answer 8

That's just the rule where a^2 and b^2 represent square numbers

Answer 9

You apply that rule to your given question.