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Chemistry 14 Online
OpenStudy (anonymous):

What would be the molarity of the solution obtained by mixing 30% by mass concentration of h2so4 and 70% by mass of h2so4. If the resultant solution has a density 1.425 g/ml.Calculate molarity

OpenStudy (anonymous):

@Peter14

OpenStudy (shubhamsrg):

re-check the question -_-

OpenStudy (anonymous):

why?

OpenStudy (shubhamsrg):

both shouldn't be h2so4

OpenStudy (anonymous):

that's what I was thinking too

OpenStudy (anonymous):

why not?

OpenStudy (shubhamsrg):

oh,,well, it can be, okay, let it be..

OpenStudy (anonymous):

there's even a equation for same solute...called Dilutional equation...

OpenStudy (anonymous):

does it give molarities for the two initial solutions? if not I haven't studied this.

OpenStudy (anonymous):

no...i gave u the whole question..

OpenStudy (anonymous):

i got molarities of both separate..i dont know how to find volume..cuz for the equation i need separate volumes and total volume..

OpenStudy (anonymous):

@shubhamsrg @Peter14 Crap! sry i frgt to give u densities... the 30% one d=1.218 70% one d=1.61..both are g/ml

OpenStudy (shubhamsrg):

the language of the question confuses me molarity = total moles/toatl volume. @Peter14 please continue! :| I am confused here.

OpenStudy (anonymous):

i'm confused here too. If I were you I would try to find a table or graph somewhere on how the concentration of h2so4 affects the density of a solution

OpenStudy (anonymous):

Also...molarity equals

OpenStudy (anonymous):

if you can't find that, I have no clue.

OpenStudy (anonymous):

and I have to go now, it's 22:37 which is past my bedtime

OpenStudy (anonymous):

(molarity of 1solute*its volume + m of 2nd solute*its volume)/total volume in litres

OpenStudy (anonymous):

@shubhamsrg does that formula help? @Peter14 goodnight...sry to have kept you awake...

OpenStudy (shubhamsrg):

thats just the formula I wrote -_-

OpenStudy (anonymous):

so? what to do?

OpenStudy (shubhamsrg):

not too sure, I wouldn't direct you wrong. Not too sure on this one.

OpenStudy (anonymous):

hmm..ok..one sec there's one more..

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