Show that the derivative of f(x) = 3x – 5 is f’(x) = 3. Explain in terms of slope why this is true.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
f'(x) = (3x-5)' = (3x)' - 5' = 3 - 0 = 3.
the slope re[resents the geometric interpretation of the derivative.
OpenStudy (anonymous):
okay there is not more information just that?
OpenStudy (anonymous):
the slope is also the tangent of the angle formed by the graph and the ox axis
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
i will draw it.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
The derivative IS the slope, so 3 makes sense is the sloe of the line, if you look at the original
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
ignore my typos, you know what i mean lol
OpenStudy (anonymous):
yea i got what you meant
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
y intercept (when the grapf intersects the oy axis): x=0 => y=-5
x intercept (when the grapf intersects the ox axis): y=0 => 3x-5=0 => x=5/3
|dw:1365619047638:dw|
OpenStudy (anonymous):
so when you want to find the tangent of that angle, which is also the slope you get \[\tan \alpha = \frac{ 5 }{ \frac{ 5 }{ 3 } } = 5 \times \frac{ 3 }{ 5 }\]