Find (dy/dx) for ye^xy=3x
this requires implicit differentiation, take the dirivative of each term is your first step
um Ive already tried to do that and that is why i came to this site
ok, for the left side: you have to use rules to take the derivative. do you know which ones?
no
your going to want to start with the product rule to derive y*e^xy
would it be y* ln^xy
have you learned how to take the derivative of 'e'? you dont need to use Ln for this
no I have not
Product rule: f'(x)g(x)+f(x)g'(x) so f(x) would be y g(x) would be e^xy in this situation, whats the derivative of y?
just y
well, your taking the derivative with respect to x, so the derivative of y would be dy/dx.
oh ok
do you remember that from class? I just want to make sure im not confusing you
no you are fine
ok, now do you rember how to find the derivative of e^xy?
ex and ey
you have to use the chain rule for this one, have you used the chain rule beore?
yes
hold on a minute ye^x
great! so use the chain rule to find the derivative of e^xy, remember the derivative of y is dy/dx.
they threw a curve at you, its 'xy' so you need to use a product rule again, inside of the chain rule
ye^x
ok, i worked out the problem. you can check my answer: dy/dx=(3-y)/(e^xy(1+xy))
ok um I checked it and it looks good
ok, i hoped that helped a little bit
yes it did thanks
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