use mathematical induction to prove the statement is true for all positive integers n the integer n^3+2n is divisible by 3 for every positive integer n
ok, so to prove something using induction whats the first step you need to do?
theres two steps
i am honestly not sure..
ok, the first step is to prove that n(1) is true
i remember a bit of that it's called your "base" i think. but what do i prove this equation against without it being equal to something?
this is more of a theorem youre proving
1^3+2(1)=?. the problems i have done like this have another equation in the "?" area
so for the first step n(1) = (1)^3 +2(1)= 1+2 = 3, so 3is divisable by 3
oh i see! yes it is
perfect!
see, its not equal to a number, they want you to show that the equation is equal to a number divisable by 3
so now that you showed its divisable by 1, you need to show step 2 which is....?
another fabulous question... sorry i don't know
lol, well whats the question asking?
i need to prove the statement true for all positive integers, but i'm going to assume that I shouldn't prove individually each number that is not negative.
well, you are going to prove each number. youre just not going to enter 2, 3, 4, 5,......into the statement.....so now the question is, do you see a pattern?
n(2) is 12 and n(3) is 33 so i can tell that they all seem divisible by 3,
if we showed it is true for 1, and we need to prove its true for EVERY natural number what you need to do is plug in "n+1" in to the statement
that will give us every natural number!
would i plug that in where all the "n" is? for example: (n+1)^3+2(n+1)
EXACTLY!! preform the binomial expansion, combine like terms and thats pretty much it. i gotta run to class now, good luck with any other problems!
thanks!
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