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Given: Quadrilateral ABCD is inscribed in Z. is tangent to Z. Prove: m∠XAD + m∠YAB = m∠C
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2 Column Proof Please
we knowed the property of a Quadrilateral is inscribed in circle, the measure opposite angles has sum 180, so according ur diagram it has to <A + <C = 180 degrees or <C = 180 - <A
also, according diagram : <XAD + <A + <YAB = 180 degrees (supplement angles)
<XAD + <A + <YAB = 180 subtract by <A from both sides <XAD + <A + <YAB - <A = 180 - <A <XAD + <YAB = 180 - <A
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because 180-<A = <C proof that : <XAD + <YAB = <C
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