Given: Quadrilateral ABCD is inscribed in Z. is tangent to Z.
Prove: m∠XAD + m∠YAB = m∠C

Question

Given: Quadrilateral ABCD is inscribed in ￼Z. ￼is tangent to ￼Z. 
Prove: m∠XAD + m∠YAB = m∠C

anonymous · Answer

anonymous · Answer

2 Column Proof Please

raden · Answer

we knowed the property of a Quadrilateral is inscribed in circle, the measure opposite angles has sum  180, so according ur diagram it has to
<A + <C = 180 degrees or
<C = 180 - <A

raden · Answer

also, according diagram :
<XAD + <A + <YAB = 180 degrees (supplement angles)

raden · Answer

<XAD + <A + <YAB = 180 
subtract by  <A from both sides
<XAD  + <A + <YAB  - <A  = 180 - <A
<XAD  + <YAB  = 180 - <A

raden · Answer

because 180-<A = <C
proof that :
<XAD  + <YAB  = <C

anonymous · Answer

Omg I love you! (No Homo of course)

anonymous · Answer

Thank You!!

raden · Answer

hehe, you're welcome ;)