An unknown gas effuses a rate that is .462 times that of nitrogen gas at same temp. Calculate the molar mas of the unknown gas in g/mol.

Given Rate of uknown / rate N2 = .462

find M uknown

rate uknown / rate N2 = sqt Mn2 / M unk

Question

An unknown gas effuses a rate that is .462 times that of nitrogen gas at same temp. Calculate the molar mas of the unknown gas in g/mol.

Given Rate of uknown / rate N2 = .462

find M uknown

rate uknown / rate N2 = sqt Mn2 / M unk

anonymous · Answer

$$ M _{unk }\frac{ M _{n2}  }{  (\frac{ rate unk}{ raten2 })^{2}} = 28.02 g/mol / (.462)^{2} = 121 g/ mol $$

anonymous · Answer

Can someone explain to me the algebra done on that equation. How they got ( r uknown / rate n2 ) ^2 and M unknown by itself?