Question

Write the equation of the circle in standard form. Find the center, radius, intercepts.
x^2 + y^2 - 8x - 6y + 9= 0

Answer 1

just put this into the form
(x-h)^2+(y-k)^2 = r^2.. soo if we do some arithmetic/algebra..

Answer 2

First get the xs and ys together into their groups
x^2-8x + y^2-6y + 9 = 0

Answer 3

(x^2 - 2 * 4 * x) + (y^2 - 2 * 3 * y) + 9 = 0

Answer 4

math makes me want to die

Answer 5

Complete the square:
(x^2 - 2 * 4 * x + 4^2) + (y^2 - 2 * 3 * y + 3^2) + 9 - 4^2 - 3^2 = 0

Answer 6

does * = multiply?

Answer 7

Yea
(x-4)^2 + (y-3)^2 + 9 - 16 - 9 = 0
(x-4)^2 + (y-3)^2 - 16 = 0
(x-4)^2 + (y-3)^2 = 16

Answer 8

which can be rewritten as:
(x-4)^2 + (y-3)^2 = 4^2

Answer 9

im just going to start emailing you my homework. end of discussion.

Answer 10

So that's in the standard form:
(x-h)^2 + (y-k)^2 = r^2

Answer 11

hey that's not very nice!

Answer 12

The center is (h;k) and the radius is r

Answer 13

I would say Hi too! :D like..." Hi! Love ya....can I have answers by 2am EST? thankkksss!"\

Answer 14

So final ans:
Circle in standard form: (x-4)^2 + (y-3)^2 = 4^2
Center: (4;3)
Radius: 4

Answer 15

i'd be asleep, so i would only read the email at 7am.. and respond at around 10pm

Answer 16

Im going to be up for a while reading this in my book and making sense of it. I take math online so I don't have much help

Answer 17

Its ok Bah Im not really going to email my homework lol.

Answer 18

ik.. just tellin you what would happen if you did lo

Answer 19

thanks for the help! <3