Consider the following table of the ages of our first six presidents Ages of the first 6 presidents at inauguration Washington 57 J. Adams 61 Jefferson 57 Madison 57 Monroe 58 JQ Adams 57 Find the mean of the data set (57+61+57+57+58+57)/6 = 347/6 = 57.83 Find the standard deviation (showing all work) How many of the presidents’ ages fall within one standard deviation of the mean?
so to find std dev it is the sq root of the variance and variance = \[1/(n-1) \sum_{i =1}^{6} (x_i - \mu_x)^2 \] and just sq root after
ok lol so what you do is \[\frac{ (57-57.83)^2+(61-57.83)^2+(57-57.83)^2+(57-57.83)^2+(58-57.83)^2+(57-57.83)^2 }{ 6- 1 }\]
then square root it and you will get the std dev
sorry I was off open study, thanks!
How many of the presidents’ ages fall within one standard deviation of the mean?
so the standard deviation would be 2.56668
actually its 1.6020861400062107
to see if it is 1 std. dev away you should take the numbers, subtract the mean then divide by the std so the first one you do \[\frac{ 57-57.83 }{ 1.602 } = -0.52\] since its greater than -1 and less than 1 might need someone to check on this though
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