Question

Solve this equation for x, 0.69=log x.
1) raise each side of the equation as the power of the base of the log
2)simplify by using the property: z=a^logaz

Answer 1

anyone?? >:\

Answer 2

Use this logarithm law:
\[\huge \log x=c\]
Where x and c are real. This logarithm form can be rewritten as:
\[\huge 10^c=x\]

Answer 3

When there is no base number next to the word log, you take it as base 10.

Answer 4

But now it asks you to raise both sides. so the log base would be 10.

Answer 5

well @Azteck so far I have 10^logx=10^0.69 is that right?

Answer 6

Yes that's correct.

Answer 7

so what do I do now? >.<

Answer 8

\[\huge z=a^{\log_{a}z}\]
Is that what you mean by the second question?

Answer 9

blaah I am so confused! I don't know why though. I was understanding everything, but now I am all no where.

Answer 10

I know I have to use that property to simplify, but I don't know how

Answer 11

I'm asking you whether the expression given is written as that. I need clarification. This is not confusing as much as trtying to interpret what you wrote in your second question.

Answer 12

trying*

Answer 13

ohh yeah that's what it was, sorry!

Answer 14

Then it's just matching numbers to their corresponding letters...
You have this:
\[\huge 10^{0.69}=10^{\log x}\]
Now you can see that z represents x and a represents 10.
\[\huge x=10^{\log_{10}x}\]
So then it's just substituting the left hand side of what you came up with int he first question with x. You just replace that whole RHS(Right Hand Side) with x.
ANd you get:
\[\huge x=10^{0.69}\]

Answer 15

I meant right hand side sorry. not left hand side.

Answer 16

Forget what I said about the left hand side and replace that with right hand side.

Answer 17

in the*

Answer 18

so, the answer is 4.90?

Answer 19

\[x=e^{0.69}\]

Answer 20

so, @Nancy_Lam the definite answer is 1.99?

Answer 21

You don't find the answer...

Answer 22

The question says simplify.

Answer 23

If it said evaluate or solve, then you find the answer.

Answer 24

let me use the calculator

Answer 25

umhm. it does say solve for x though...

Answer 26

Then you should of posted that with your questions. That would of been better for all of us to help you get your answer as quick as possible.

Answer 27

I did post it, at the beginning...

Answer 28

And @Nancy_Lam is using natural log. I don't think she has done log to the base e.

Answer 29

x=1.99372 round = 1.99 you are right

Answer 30

http://www.wolframalpha.com/input/?i=0.69%3Dlog+x

Answer 31

What do you mean @Azteck ??

Answer 32

If 1.99 is the correct answer your first part will be wrong because you raised both sides by base 10.

Answer 33

you should of raised both sides by base e if you do that.

Answer 34

When you get into calculus, everytime you see log, you always assume it is to the base e. But if you haven't gone passed integration etc, then you assume log to be base 10.

Answer 35

past*

Answer 36

unless stated otherwise.

Answer 37

(/.<) ayayayy....

Answer 38

Have you learnt anything on differentiating e^x? If you haven't done that, then it's unlikely 1.99 is the correct answer.

Answer 39

I see what you mean... I have to start all over again, I am confused.
By the way Thanks ALOT @Azteck & @Nancy_Lam

Answer 40

No worries.