Question

(1/(e^x))(sqrt(1+(e^(-x^2))))dx? <-- how?

Answer 1

\[\int\limits_{0}^{\infty} (1/e^x)\sqrt(1+(1/e^(x^2)))dx <--more specifically\]

Answer 2

if I do:
u = 1/(e^x)
du = -e^(-x)

I would eliminate the first e^-x
giving me:

-integral of sqrt(1 + u^2)du

but this one would make it messier because of tan^2theta.

I checked wolfram and it gave me e^(-x) sqrt(e^(-x^2)+1) but i dunno how this is.

Answer 3

\(\left(\dfrac1{e^x}\right)^2\neq\dfrac1{e^{-x^2}}\)

Answer 4

Give us the correct problem please.

Answer 5

ok sorry. that would be

1/(e^(x^2))

Answer 6

retype ur equation from int (........./......) dx

Answer 7

int ( (1/e^x) (sqrt( 1 + ( 1/ (e^(x^2) ) ) ) dx

Answer 8

is this any better?

Answer 9

If it's really \(e^{x^2}\), good luck.

Answer 10

Yeah, I dunno how to do e^x^2. If nothing else, ill just copy paste what wolfram said and hope the prof thinks i know how to do it.

Answer 11

Do you mean \(e^{x^2}\) or \((e^x)^2\)?

Answer 12

(1/(e^x))^2

Answer 13

aw. sorry.
it was originally (1/(e^x))^2
so that would have given me
(1/e^2x)
I was wrong. aw.

Answer 14

you know what? just nevermind this. thanks though. ill just skip this for now.