Question

A bag contains 6 red marbles, 4 blue marbles, 7 green marbles, and 3 yellow marbles. A marble is drawn from the bag and is not replaced. Then a second marble is drawn. What is the probability that both marbles drawn were red?

Answer 1

.

Answer 2

the probability that the first one is red, times the probability that the second one is red given that the first one is red

Answer 3

45/637 then? Thank you!

Answer 4

i didn't check, but it should be
\[\frac{6}{20}\times \frac{5}{19}\]

Answer 5

which is definitely not \(\frac{45}{637}\)

Answer 6

ok it's .0789473684

Answer 7

which is 3/38?

Answer 8

\[\frac{6}{20}\times \frac{5}{19}=\frac{6}{4\times 19}=\frac{3}{38}\]

Answer 9

yeah that is it

Answer 10

ok, thank you so much!